Patterns and Puzzles (Preparatory Stage Math)
Worksheet A: Concepts
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Answer
AB.
Solution
The block “AB” repeats; after three blocks, the next block is again A then B.
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Answer
ABCABC; unit = ABC.
Solution
ABC repeats as a 3-letter block; ABAB has a 2-step unit AB, not 3.
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Answer
Circle (no straight sides).
Solution
Triangle has 3, square 4 sides; circle has none, so it breaks the “polygon with sides” rule.
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Answer
Same shape mirrored.
Solution
Mirror symmetry reflects across the middle line to complete the whole figure.
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Answer
10, 12.
Solution
Add 2 each time; the sequence increases evenly by a fixed step.
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curve, straight.
Solution
AB repeats; after straight (A) comes curve (B), then straight again.
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4 triangles.
Solution
Each square uses 2 triangles; two squares need 2×2 = 4 triangles.
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Answer
Blue triangle.
Solution
Others either are red or square; the blue triangle is neither, breaking the rule.
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Answer
B.
Solution
8 days is 2 cycles (6) plus 2 more: A→B→C→A→… After 8, land on B.
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Answer
Right.
Solution
Quarter-turn clockwise moves “up” to “right” in orientation.
Worksheet B: Computational Skills
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Answer
20, 25.
Solution
Add 5 every step to extend the sequence correctly.
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Answer
40, 50.
Solution
Place-value skip counting in tens gives the intermediate values.
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Answer
11, 14.
Solution
Add 3 repeatedly; the pattern increases linearly.
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13, 16.
Solution
Apply the same rule to each input; outputs follow the pattern consistently.
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Answer
11, 10.
Solution
Apply +2 then −1 alternately: …, 9 +2→11, then −1→10.
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Answer
tri = 6, sq = 2.
Solution
Cycle length 3 with 2 triangles, 1 square; 8 items → two full cycles (6 items) + 2 more = 6 triangles, 2 squares.
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Answer
1, 3, 5, 7, 9, 11, 13, 15.
Solution
Odd numbers increase by +2 starting at 1 up to the limit.
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Answer
16, 24.
Solution
Counting by 4s fills the intermediate values: 12, 16, 20, 24, 28.
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Answer
15; “add 6 to odd inputs.”
Solution
Each output is input + 6; extend 9→15 accordingly.
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Answer
Output for 6 = 11; input for 13 = 7.
Solution
6→2×6−1=11; to solve backward, (x×2)−1=13 → x×2=14 → x=7.
Worksheet C: Problem-Solving & Modeling
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Answer
R (example shown).
Solution
With 7 days and a cycle of length 3, the first item (R) will appear one extra time.
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Answer
Mirror the positions: 3 near the centerline, 2 at the outer edge on the right wing.
Solution
Symmetry requires equal-distance mirrored placements across the midline.
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About 3 or 4 depending on cut; with 10 places starting at square, circles appear at positions 2,5,8 → 3 circles.
Solution
Cycle length 3 with one circle per cycle; 10 items give 3 full cycles (3 circles) plus a start of the next cycle.
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Answer
0, 3, 6, 9; it matches skip-count by 3s.
Solution
Multiplying by 3 produces the 3-times table sequence used for skip counting.
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25; it is >20, <30, and odd.
Solution
Check all conditions; 21, 23, 25, 27, 29 would also fit this rule.
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0° (back to start).
Solution
After a full 360°, the orientation repeats; 270°→0° resets the cycle.
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Answer
6, 12, 16.
Solution
Start 2; +4→6; ×2→12; +4→16; repeat the two-step rule.
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A=6, B=6.
Solution
Block length 4 (AABB) has 2 As and 2 Bs each; 12 items = 3 full blocks → equal counts.
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Answer
1, 3, 6, 8, 11, 13, 16.
Solution
Add 2, then 3 alternately to extend: 1→3→6→8→11→13→16.
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Answer
2, 4, 6 (any order).
Solution
All three distinct values sum to 12; any permutation meets the constraint.
Two best activities
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Answer
Create repeating borders (AB, ABB, AABB) and floor tilings with triangles/squares; label the smallest repeating block (unit) each time.
Solution
Provide paper shapes or stamps. Learners build borders and tilings, circle the repeat unit, and count how many of each tile appear in 10–12 places. They then swap designs and identify the unit in peers’ work, strengthening pattern recognition and communication.
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Answer
Run “function machines” (+3, +5, ×2, double-then−1) on input cards, chart outputs, and match to skip-counts or growing patterns.
Solution
Set stations with machine cards. Teams feed inputs 0–12, record outputs, and draw a quick number line showing steps. They explain rules in words, compare machines that produce the same skip-count, and design one “two-rule” machine to share with the class.